I'm getting the following error issuing a find in cron:
find: 0652-018 An expression term lacks a required parameter.
Here's my crontab entry:
0 23 * * * find /orafra/flash_recovery_area/exportArea -type f -mtime +6 -exec rm -f {} \;
After research and a lot of googling, I found out that cron is eating up some symbols, specifically the backslash "\" and the semicolon ";"
With that, here's my now working crontab entry:
0 23 * * * find /orafra/flash_recovery_area/exportArea -type f -mtime +6 -exec rm -f {} \\\;
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